3.1 ~g of a compound, ' X ' (molar mass =62 ~g mol ⁻¹ ) is dissolved in 19.5 ~g of other compound, Y (molar mass =78 ~g ~mol ⁻¹ ). The ratio of mole fractions of X and Y in the solution is

Step-by-step solution

( ) The number of moles of X= W_X M_X = 3.1 ~g 62 ~g ~mol ⁻¹ =0.05 ~mol The number of moles of Y= W_Y M_Y = 19.5 ~g 78 ~g ~mol ⁻¹ =0.25 ~mol Mole fraction of X= Moles of X Total moles = 0.05 0.75 =0.066 Mole fraction of Y= Moles of Y Total moles = 0.25 0.75 =0.33 The ratio of mole fraction of X and Y= 0.066 0.33 = 1 5 .