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KVPY2017MathematicsQuadratic Equation

If a, b, c are real numbers such that a+b+c=0 and a²+b²+c²=1 , then (3 a+5 b-8 c)²+(-8 a+3 b+5 c)²+(5 a-8 b+3 c)² is equal to

Options

  1. A49
  2. B98
  3. C147
  4. D294

Correct answer

C. 147

Step-by-step solution

Expanding are get array l 98 (a²+b²+c² )-98(a b+b c+c a) =98-98 (- 1 2 ) =147 array

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