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KVPY2014MathematicsQuadratic Equation

Let r be a root of the equation x²+2 x+6=0 . The value of (r+2)(r+3)(r+4)(r+5) is equal to .

Options

  1. A51
  2. B-51
  3. C-126
  4. D126

Correct answer

C. -126

Step-by-step solution

r be a root r²+2 r+6=0 ...... (1) array l now (r+2)(r+3)(r+4)(r+5) = (r²+5 r+6 )(r 2+9 r+20) =(3 r)(7 r+14) using (i) =21 (r²+2 r ) & =-126 using (i) array

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