KVPY2016MathematicsSequences and Series
The number of triples (x, y, z) of real numbers satisfying the equation x⁴+y⁴+z⁴+1=4 x y z is
Options
- A0
- B4
- C8
- Dmore than 8
Correct answer
B. 4
Step-by-step solution
(x, y, z) are real & x⁴, y⁴, z⁴ are positive real numbers array l x⁴+y⁴+z⁴+1 4 |x y z| (x y z) |x y z| i.e., x y z>0 array So it holds equality x ⁴= y ⁴= z ⁴=1 ; But xyz >0 ( x , y , z ) (1,1,1),(1,-1,-1),(-1,1,-1),(-1,-1,1) So no. of triplets is 4 .