0.05 mole of a non-volatile solute is dissolved in 500 ~g of water. What is the depression in freezing point of resultant solution? (K_f ( H ₂ O )=1.86 ~K ~kg ~mol ⁻¹ )

Step-by-step solution

Given, n=0.05 ~mol aligned V & =500 ~g of water K_f & =1.86 k kg / mol T_f & =? aligned Molality = Number of moles Weight of solvent ( kg ) = 0.05 0.5 T_f=m K_f= 0.05 0.5 1.86=0.186 ~K