The number of real solutions of the equation 2sin 3 x+ 7 x-3=0 which lie in the interval [-2 , 2 ] is

Step-by-step solution

only possible when 3 x=1 & 7 x=1 3 x=1 array l 3 x= (4 n+1) 2 , n I 3 x=(4 n+1) 2 x=(4 n+1) 6 7 x= (4 m+1) 2 , m I x=(4 m+1) 14 array for common solution (4 n+1) 6 =(4 m+1) 14 Solving these 1=3 ~m -7 n First solution is m=5, n=2 Second solution is m =12, n =5 So two solutions are possible