2 ~g of a non-electrolyte solute (molar mass is 500 ~g ~mol ⁻¹ ) was dissolved in 57.3 ~g of xylene. If the freezing point depression constant K_f of xylene is 4.3 ~K ~kg ~mol ⁻¹ . Then, the depression in freezing point of xylene is........

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2 ~g of a non-electrolyte solute (molar mass is 500 ~g ~mol ⁻¹ ) was dissolved in 57.3 ~g of xylene. If the freezing point depression constant K_f of xylene is 4.3 ~K ~kg ~mol ⁻¹ . Then, the depression in freezing point of xylene is..........

Quantrex Academy · Accepted Answer

Correct answer: B. 0.3 ~K

T_f=K_f w₁ 1000 w₂ m₁ aligned & w₁= weight of solute & w₂= weight of solvent & m₁= molar mass of solute & K_f=4.3 ~K ~kg ~mol ⁻¹ aligned Now, T_f=4.3 2 1000 57.3 500 = 17.2 57.3 =0.30 ~K

2 ~g of a non-electrolyte solute (molar mass is 500 ~g ~mol ⁻¹ ) was dissolved in 57.3 ~g of xylene. If the freezing point depression constant K_f of xylene is 4.3 ~K ~kg ~mol ⁻¹ . Then, the depression in freezing point of xylene is..........

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