KVPY2017PhysicsGravitation
Two satellites S₁ and S₂ are revolving around a planet in the opposite sense in coplanar circular concentric orbits. At time t =0 , the satellites are farthest apart. The periods of revolution of S₁ and S₂ are 3 ~h and 24 ~h respectively. The radius of the orbit of S₁ is 3 10⁴ ~km . Then the orbital speed of S ₂ as observed from
Options
- Athe planet is 4 10⁴ ~km ~h ⁻¹ when S ₂ is closest from S ₁ .
- Bthe planet is 2 10⁴ ~km ~h ⁻¹ when S ₂ is closest from S ₁ .
- CS₁ is 10⁴ ~km ~h ⁻¹ when S ₂ is closest from S ₁
- DS₁ is 3 10⁴ ~km ~h ⁻¹ when S ₂ is closest from S ₁
Correct answer
D. S₁ is 3 10⁴ ~km ~h ⁻¹ when S ₂ is closest from S ₁
Step-by-step solution
T ² r ³ array l 9 24² = ( 3 10⁴ r³ )³ 3 3 24 24 = ( 3 10⁴ r )³ 1 4 = 3 10⁴ r r=12 10⁴ array orbital speed of S₂ seen from planet = ₂ r array l = 2 24 12 10⁴ = 10⁴ ~km ~h ⁻¹ ~V ₁= ₁ r ₁= 2 3 3 10⁴ 2 10⁴ ~km ~h ⁻¹ array ( 2 3 + 2 24 ) t = 9 t 24 = 1 2 t = 12 9 hr Angle rotate by both satellite array l ₁= 2 3 12 9 8 9 ₂= 2 24 12 9 9 array velocity of S₂ seen from S₁=V₁+V₂ =3 10⁴ ~km ~h ⁻¹