KVPY2015PhysicsGravitation
A ball is launched from the top of Mt. Everest which is at elevation of 9000 ~m . The ball moves in circular orbit around earth. Acceleration due to gravity near the earth's surface is g . The magnitude of the ball's acceleration while in orbit is
Options
- Aclose to g / 2
- Bzero
- Cmuch greater than g .
- Dnearly equal to g .
Correct answer
D. nearly equal to g .
Step-by-step solution
m v² r =m g^ (where g ' is nearly equal to g )