A bottle has a thin nozzle on top. It is filled with water, held horizontally at a height of 1   m and squeezed slowly by hands so that the water jet coming out of the nozzle hits the ground at a distance of 2   m . If the area over which the handss s sare which the hands squeeze it is 10   cm 2 , the force applied by hands is close to (take g = 10   m / s 2 and density of water = 1000   kg /

Step-by-step solution

Apply Bernoulli between point- 1 and point- 2 . P 1 + 1 2 ρ V 1 2 = P 2 + 1 2 ρ V 2 2 P 1 = P atm  +  Force by hand   Area  V 1 tends to zero becomes area of point- 2 is very small. P 2 = P atm P atm  + F / A = P atm  + 1 / 2 ρ V 2 2 ⇒ V 2 2 = 2 F P A   … i From Kinematics. 2 = 2 (   h ) g × V 2 ∴ V 2 2 = 20   … ii Using (i) and (ii) we get 20 = 2 F ρ A   ∴ F = 10   N