x ~g ^ MgSO ₄(i=1.8) is in 2.5 ~L of solution has an osmotic pressure of 2.463 ~atm at 27^ C . What is the value of x in g ?

Step-by-step solution

Given, Mass of MgSO ₄(w)=x ~g vant Hoff factor (i)=1.8 Volume of solution (V)=2.5 ~L Osmotic pressure ( )=2.463 ~atm Temperature (T)=27+273=300 ~K Molar mass of MgSO ₄=24+32+64=120 ~g ~mol ⁻¹ aligned & =i C R T=i w M 1 V R T & =2.463= i x R T M V & = 1.8 x 8.314 300 120 2.5 ( R=0.82 ~L - atm K ⁻¹ ~mol ⁻¹ ) & & = 2.463 120 2.5 1.8 0.082 300 x & = 738.9 44.28 =16.68 16.6 ~g aligned Hence, option (d) is the correct answer.