100 ~mL of 1.5 %( w / v ) solution of urea is found to have an osmotic pressure of 6.0 ~atm and 100 ~mL of 3.42 %(w / v) solution of cane sugar is found to have an osmotic pressure of 2.4 ~atm . If the two solutions are mixed the osmotic pressure of the resulting solution in atm is (Assume that there is no reaction between urea and cane sugar)

Step-by-step solution

(c) Key Idea Firstly, we calculate the osmotic pressure of each solution by using the formula =C R T and then, calculate the total osmotic pressure. aligned Given, w₁( urea ) & =1.5 ~g V₁( urea ) & =100 ~mL M₁ & =60 ~g / mol w₂( cane sugar ) & =3.42 ~g V₂( cane sugar ) & =100 ~mL M₂ & =342 ~g / mol ₁( urea ) & = w₁ 100 M₁ V₁ R T ₁( urea ) & = 1.5 1000 60 200 0.0821 298 ₁( urea ) & =3.05 ~atm aligned Now, aligned & ₂( cane sugar )= w₂ M₂ V₂ 1000 R T = & 3.42 1000 342 200 1000 0.0821 298 aligned Thus, the osmotic pre