If CO ₂ gas having a partial pressure of 1.67 bar is bubbled through l L water at 298 ~K , the amount of CO ₂ dissolved in water in g L ⁻¹ is approximately. (Henry's law constant of CO ₂ is 1.67 k bar at 298 ~K )

Step-by-step solution

Let p_A be the partial pressure of CO ₂ and _A be its mole fraction p_A=K_ H _A( Henry's law) 1.67 bar =1.67 k bar _A (where, x_A=0.001 ) or n_A n_B =0.001 [ Number of moles of water =55 ] aligned n_A & =0.001 55.55 n_A & =0.056 aligned aligned & n= Given mass (m) Molecular mass (M) =0.056 & m=0.056 44=2.44 ~g & Thus, 2.44 ~g of CO ₂ is dissolved in 1 ~L water at & 298 ~K . aligned 298 ~K .