Ice in a freezeris at -7⁶ C .100 ~g of this ice is mixed with 200 ~g of water at 15^ C . Take the freezing temperature of water to be 0^ C , the specific heat of ice equal to 2.2 ~J / g ^ C , specific heat of water equal to 4.2 ~J / g ^ C ,

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Ice in a freezeris at -7⁶ C .100 ~g of this ice is mixed with 200 ~g of water at 15^ C . Take the freezing temperature of water to be 0^ C , the specific heat of ice equal to 2.2 ~J / g ^ C , specific heat of water equal to 4.2 ~J / g ^ C , and the latent heat of ice equal to 335 ~J / g . Assuming no loss of heat to the environment, the mass of ice in the final mixture is closest to

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Correct answer: B. 67 ~g

Let mgm of ice melted Mixture will be at 0^ C Heat given =200 (4.2)(15) J Heat absorbed =100 2.2 (7)+m(335) by solving m =33 gm So ice remain =100-33=67 ~g

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