KVPY2016PhysicsThermal Properties of Matter
A nuclear fuel rod generates energy at a rate of 5 10⁸ Watt / m ³ . It is in the shape of a cylinder of radius 4.0 ~mm and length 0.20 ~m . A coolant of specific heat 4 10³ ~J /( kg - K ) flows past it at a rate of 0.2 ~kg / s . The temperature rise in this coolant is approximately -
Options
- A2^ C
- B6^ C
- C12^ C
- D30^ C
Correct answer
B. 6^ C
Step-by-step solution
dm dt S T = d dt d dt =5 10⁸ volume of rod =5 10⁸ (4)² 10⁻⁶ 0.2 10 =5 10 16 2=1600 0.2 4 10³ T =1600 8 10² T =16 10² T =3.14 2 6.28^ C