KVPY2015PhysicsThermal Properties of Matter
1 Kg of ice at -20^ C is mixed with 2 Kg of water at 90^ C . Assuming that there is no loss of energy to the environment, what will be the final temperature of the mixture? (Assume latent heat of ice =334.4 KJ / Kg , specific heat of water and ice are 4.18 ~kJ /( kg K ) and 2.09 ~kJ /( kg K ) , respectively.)
Options
- A30^ C
- B0^ C
- C80^ C
- D45^ C
Correct answer
A. 30^ C
Step-by-step solution
m_ i s_ i ( T)+m_ i L+m_ i s_ w (T-0)=m_ w s_ w (90-T)1 2.09(20)+1 334.4+1 4.18 T=2 4.18 (90-T)T=60-30=30^ C