AP EAMCET201822 Apr 2018Morning ShiftChemistrySolutionsActual
Dissolving 120 ~g of a compound (mol. wt =60 ) in 1000 ~g of water gave a solution of density 1.12 ~g ~mL ⁻¹ . The molarity of solution is
Options
- A1.0 M
- B2.0 M
- C2.5 M
- D4.0 M
Correct answer
B. 2.0 M
Step-by-step solution
Given, density (d)=1.12 ~g ~mL ⁻¹ Mass of solute (w)=120 ~g aligned & Molar mass of solute (M)=60 & Mass of solvent (w)=1000 ~g =1000 ~mL & Total mass =1000+120=1120 ~g & d= Mass Volume (V) & Total volume (V)= 1120 1.12 =1000 ~mL & Molarity (c)= w M 1000 V & Molarity (c)= w m 1000 1000 = 120 60 =2.0 ~m aligned