KVPY2016PhysicsThermodynamics
The heat capacity of one mole an ideal is found to be CV =3 R (1+ aRT ) / 2 where a is a constant. The equation obeyed by this gas during a reversible adiabatic expansion is -
Options
- ATV ^ 3 / 2 e ^ aRT = constant
- BTV ^ 3 / 2 e ^ 3 aRT / 2 = constant
- CTV ^ 3 / 2 = constant
- DTV ^ 3 / 2 e ^ 2 aRT / 3 = constant
Correct answer
A. TV ^ 3 / 2 e ^ aRT = constant
Step-by-step solution
Adiabatic process array l TV ^ -1 = C =1+ 2 f TV ^ 2 f = C C _ V = f R 2 = 3 R (1+ aRT ) 2 f R 2 = 3 Re ^ aRT 2 2 f = 2 3 e ^ aRT array array l TV ^ 2 3 e ^ aRT = C TV ^ 3 e ^ aRT 2 = C array Ans. given is TV ^ 3 2 e ^ aRT So no option is matching may be due to printing mistake.