KVPY2013PhysicsThermodynamics
The three processes in a thermodynamic cycle shown in the figure are : Process 1 2 is isothermal; Process 2 3 is isochoric (volume remains constant); Process 3 1 is adiabatic. The total work done by the ideal gas in this cycle is 10 ~J . The internal energy decreases by 20 ~J in the isochoric process. The work done by the gas in the adiabatic process is -20 ~J . The heat added to the system in the isothermal process
Options
- A0 ~J
- B10 ~J
- C20 ~J
- D30 ~J
Correct answer
D. 30 ~J
Step-by-step solution
Q _ 1 2 = W ₁₂ w _ Total = W ₁₂+ W ₃₁10= w ₁₂-20 Q ₁₂= w ₁₂=30 ~J