KVPY2020PhysicsWave Optics
A right-angle isosceles prism is held on the surface of a liquid composed of miscible solvents A and B of refractive index n A = 1 . 50 and n B = 130 , respectively. The refractive index of prism is n p = 1 . 5 and that of the liquid is given by n L = C A n A + 1 - C A n B , where C A is the percentage of solvent A in the liquid:- If θ C is the critical angle at prism-liquid interface, the plot which best repres
Correct answer
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Step-by-step solution
n p sin θ C = n L sin 90 ° θ C = sin - 1 n L n P θ C = sin - 1 C A n A + 1 - C A n B 1 . 5 → Graph between θ C and C A will be curve of sin - 1 , Check for C A = 0 . 5 , to find most appropriate graph θ C = sin - 1 0 . 5 ( 1 . 5 ) + 0 . 5 ( 1 . 3 ) 1 . 5 θ C = sin - 1 14 15 ≃ 69 ° ∴ Correct option is (A)