A uniform thin rod of length 2 ~L and mass m lies on a horizontal table. A horizontal inpulse J is given to the rod at one end. There is no friction. The total K.E. of the rod just after the impulse will be :

Question

Quantrex Academy · Accepted Answer

Correct answer: C. 2 ~J ² / m

J = mv J . L = M (2 ~L )² 12 ^ v = J / M Cm J . L= M L² 3 = 3 J M L ke = J ² 2 ~m + 3 ~J ² 2 ~m =2 ~J ² / m

A uniform thin rod of length 2 ~L and mass m lies on a horizontal table. A horizontal inpulse J is given to the rod at one end. There is no friction. The total K.E. of the rod just after the impulse will be :

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