KVPY2016PhysicsWork, Power and Energy
Water falls down a 500.0 ~m shaft to reach a turbine which generates electricity. How much water must fall per second in order to generate 1.00 10⁹ Watts of power? (Assume 50 % efficiency of conversion and . g =10 ~m / s ² )
Options
- A250 ~m ³
- B400 ~m ³
- C500 ~m ³
- D200 ~m ³
Correct answer
B. 400 ~m ³
Step-by-step solution
500 ~m [ array c P = mah time = P _ cut P _ input P _ in = P _ cut array .= 10⁹ 0.5 P_ in =2 10⁹ mah time =2 10⁹ ~m / t = 2 10⁹ 10 500 = 2 5 10⁶=4 10⁵=400 ~m ³