The molar mass of a solute X in g mol ⁻¹ , if its 1 % solution is isotonic with a 5 % solution of cane sugar (molar mass =342 ~g ~mol ⁻¹ ), is

Step-by-step solution

For isotonic solutions aligned & W₁ V₁ m₁ = W₂ V₂ m₂ & W₁ V₁ =1, W₂ V₂ =5 & m₁= ?, m₂=342 & 1 m₁ = 5 342 or & m₁= 342 5 or & m₁=68.4=X & aligned