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Manipal MET2019ChemistryChemical Bonding and Molecular Structure

In the process, O ₂⁺ O ₂²⁺+e⁻ the electron lost is from

Options

  1. Abonding -orbital
  2. Bantibonding -orbital
  3. C2 p_z orbital
  4. D2 p_x orbital

Correct answer

A. bonding -orbital

Step-by-step solution

gathered (a) O ₂⁺- O ₂²⁺+e⁻ O ₂⁺ has (15 e e^p= 1 s^2, ^* 1 s^2, 2 s^2, ^* 2 s^2 . 2 p_x^2, 2 p_y^2, 2 p_z^2, ^* 2 p_y^1 gathered So O ₂⁺ lost a electron to form O ₂²⁺ , the e⁻ is So O ₂⁺ lost a electron to form O ₂²⁺ , the e⁻ is from antibonding orbital.

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