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Manipal MET2013ChemistryClassification of Elements and Periodicity in Properties

Calculate the electronegativity of chlorine from bond energy of Cl - F bond ( 61 kcal mol ⁻¹ ) F - F (38 kcal mol ⁻¹ ) and Cl - Cl bond ( 58 kcal mol ⁻¹ ) and electronegativity of fluorine 4.0 eV

Options

  1. A1.42 eV
  2. B1.89 eV
  3. C2.67 eV
  4. D3.22 eV

Correct answer

D. 3.22 eV

Step-by-step solution

Based on Pauling's scale ( EN )_ F -( EN )_ Cl =k =0.208 where, = resonance energy and k= conversion factor which is 0.208 for converting k cal into eV . aligned & =( BE )_ Cl - F - ( BE )_ Cl - Cl ( BE )_ F - F & =61- 58 38 & =61-46.95=14.05 kcal ( EN )_ Cl & =( EN )_ F -0.208 & =4.0-0.208 14.05 & =4.0-0.78=3.22 eV . aligned

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