If 200 mL of a 0.031 molar solution of H ₂ SO ₄ are added to 84 mL of a 0.150 M KOH solution, what is the pH of the resulting solution?

Step-by-step solution

aligned & mmol of H ⁺ (initial) =200 0.031 2=12.4 & mmol of OH ⁻ (initial) =84 0.15=12.6 & mmol of OH ⁻( left ) after neutralisation =0.2 & [ OH ⁻ ]_ final = 0.2 284 =7 10⁻⁴ M & pOH =3.15 and pH =10.85 aligned