The formation of oxide ion O ²⁻( g ) require first an exothermic and then an endothermic step as shown below: aligned & O ( ~g )+e⁻ O ⁻(g) ; H^ =-142 ~kJ ~mol ⁻¹ & O ⁻(g)+e⁻ O ²⁻(g) ; H^ =844 ~kJ ~mol ⁻¹ aligned This is because

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Correct answer: C. O ⁻ ion will tend to resist the addition of another electron

The formation of oxide ion O ²⁻( g ) require first an exothermic and then an endothermic step because the O ⁻ ion will tend to resist the addition of another electron.

The formation of oxide ion O ²⁻( g ) require first an exothermic and then an endothermic step as shown below: aligned & O ( ~g )+e⁻ O ⁻(g) ; H^ =-142 ~kJ ~mol ⁻¹ & O ⁻(g)+e⁻ O ²⁻(g) ; H^ =844 ~kJ ~mol ⁻¹ aligned This is because

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