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An aqueous solution freezes at -0.186^ C , then elevation in boiling point is (K_b=0.512, K_f=1.86 )

Options

  1. A0 . 0512^ C
  2. B100.0512^ C
  3. C-0.0512^ C
  4. DNone of these

Correct answer

A. 0 . 0512^ C

Step-by-step solution

Elevation in boiling point T_b=K_b m Dipression in freezing point aligned & T_f=K_f m & T_b T_f = K_b K_f aligned aligned T_b 0.186 & = 0.512 1.86 T_b & =0.0512^ C aligned

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