Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
Manipal MET2015ChemistrySolutions

Calculate the molal depression constant of a solvent which has freezing point 16.6^ C and latent heat of fusion 180.75 ~J / g .

Options

  1. A2.68
  2. B3.86
  3. C4.68
  4. D2.86

Correct answer

B. 3.86

Step-by-step solution

Given, aligned T_ f & =273+16.6=289.6 ~K L_f & =180.75 ~J / g R & =8.314 ~J / K / mol aligned K_f= ?, array ll & K_f= R T_f^2 1000 L_f = 8.314 (289.6)^2 1000 180.75 & K_f=3.86 array

Practice Solutions on Quantrex Academy →

More from Solutions

Identify the law which is stated as "For any solutions, the partial vapour pressure of each volatile component in the solution is directly proportional to its mole fraction". 2026The system that forms maximum boiling azeotrope is: 2026When 1 mole of benzene is mixed with 1 mole of toluene, the vapours will contain 2026A 5% solution (by mass) of cane sugar in water has a freezing point of 271 K. The freezing point of a 5% solution (by mass) of glucose in water is: [freezing point of pure water: 2 20260.02M solution of sucrose is isotonic with 0.008M solution of sodium sulphate. What is the percentage dissociation of the electrolyte? 2026What is the percentage dissociation of 0.8ml of Acetic acid (density is 1.04g/ml) which is dissolved in 1.2L of water if the observed Depression in freezing point is 0.0228 K? ( K_ 2026Identify the correct statement 2026An aqueous solution of an unknown solute "X" is prepared by adding 4.0g of it into 2.0moles of water. What is the mass percent of "X" in the aqueous solution? 2026 Full Solutions list All Manipal MET PYQs