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The relative lowering of vapour pressure of an aqueous solution containing a non volatile solute is 0.0125 . The molality of the solution is

Options

  1. A0.70
  2. B0.30
  3. C0.125
  4. D0.07

Correct answer

A. 0.70

Step-by-step solution

According to Raoult's law, "Relative lowering of vapour pressure = mole fraction of solute" (X_B )=0.0125 array rr & X_B= m M_A 10000+m M_A & 0.0125= m 18 1000+m 18 12.5+0.225 m=18 m & 17.775 m=12.5 & m= 12.5 17.775 =0.70 array

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