Manipal MET2017ChemistryStructure of Atom
The energy of second Bohr orbit of the hydrogen atom is -328 ~kJ ~mol ⁻¹ , hence the energy of fourth Bohr orbit would be
Options
- A-41 ~kJ ~mol ⁻¹
- B-1312 ~kJ ~mol ⁻¹
- C-164 ~kJ ~mol ⁻¹
- D-82 ~kJ ~mol ⁻¹
Correct answer
D. -82 ~kJ ~mol ⁻¹
Step-by-step solution
Energy of electron in n th orbit of hydrogen, E_n=- E n^2 where, E is a constant. E₂ E₄ = (n₄ )^2 (n₂ )^2 -328 E₄ = (4)^2 (2)^2 E₄= -328 4 16 =-82 ~kJ ~mol ⁻¹