Manipal MET2013ChemistryStructure of Atom
₇¹⁴ ~N + ₀^1 n ₆¹⁴ C + ₁^1 H is written as
Options
- A₇¹⁴ ~N (n, e) ₁^1 H
- B₇¹⁴ ~N (p, n) ₆¹⁴ C
- C₇¹⁴ ~N (n, p) ₆¹⁴ C
- D₆¹⁴ C (p, n) ₇¹⁴ ~N
Correct answer
C. ₇¹⁴ ~N (n, p) ₆¹⁴ C
Step-by-step solution
₇¹⁴ ~N + ₀^1 n ₆¹⁴ C + ₁^1 H This reaction can be represented as ₇¹⁴ ~N (n, p) ₆¹⁴ C