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Manipal MET2018MathematicsApplication of Derivatives

The minimum value of x^2+ 1 1+x^2 is, at

Options

  1. Ax=0
  2. Bx=1
  3. Cx=4
  4. Dx=3

Correct answer

A. x=0

Step-by-step solution

Let f(x)=x^2+ 1 1+x^2 On differentiating w.r.t. x , we get f^ (x)=2 x- 1 (1+x^2 )^2 2 x For a minimum, put f^ (x)=0 x=0 So, the function has minimum value at x=0 .

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