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Manipal MET2016MathematicsArea Under Curves

The area bounded by the parabolas y^2=4 a(x+a) and y^2=-4 a(x-a) is

Options

  1. A16 3 a^2
  2. B8 3 a^2
  3. C4 3 a^2
  4. DNone of these

Correct answer

A. 16 3 a^2

Step-by-step solution

Required area =4 ₀^a 4 a(a-x) d x aligned & =4 2 a [ -2(a-x)^ 3 / 2 3 ]₀^a & = 16 3 a^2 aligned

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