Manipal MET2019MathematicsContinuity and Differentiability
Let f(x)=x^p ( 1 x ) , when x 0 and f(x)=0 , when x=0 . Then f(x) will be differentiable at x=0 , if
Options
- Ap 0
- Bp 1
- C0 p 1
- D1 2 p 1
Correct answer
B. p 1
Step-by-step solution
Given that, f(x)= aligned x^p ( 1 x ), & x 0 0, & x=0 aligned .f(x) will be differentiable at x=0 , if _ x 0 f(x)-f(0) x-0 exists finitely. _ x 0 x^p ( 1 x ) x exists finitely _ x 0 x^ p-1 ( 1 x ) exists finitely p-1 0 p 1