The approximate value of ₁^5 x^2 d x using trapezoidal rule with n=4 is

Step-by-step solution

aligned & ₁^5 x^2 d x & = 4 4 [ 1 2 f(1)+f(2)+f(3)+f(4)+ 1 2 f(5) ] & = 1 2 [x^2 F (x^2 )- F (x^2 ) d (x^2 ) ] & = [ 1 2 +4+9+16+ 25 2 ]=42 [u sing f(x)=x^2 ] aligned