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Manipal MET2018MathematicsDifferential Equations

If x (1+y^2 ) d x+y (1+x^2 ) d y=0 and y(0)=1 then x^2 y^2+x^2+y^2 is equal to

Options

  1. A0
  2. B1
  3. C2
  4. D3

Correct answer

B. 1

Step-by-step solution

Given that, aligned x (1+y^2 ) d x+y (1+x^2 ) d y & =0, y(0)=1 x 1+x^2 d x+ y 1+y^2 d y & =0 aligned On integrating both sides, we get 1 2 (1+x^2 )+ 1 2 (1+y^2 )=c Now, array rlrl & & y(0)=1 c= 1 2 (1+1) & = 1 2 2 & & & 1+x^2 1+y^2 = & & 2 & & (1+x^2 ) (1+y^2 ) & =2 & & x^2+y^2+x^2 y & =1 array

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