The motion of a particle along a straight line is described by the function x=(2 t-3)^2 , where x is in metre and t is in second. Then, the velocity of the particle at origin is

Step-by-step solution

Given that, x=(2 t-3)^2 On differentiating w.r.t. x , we get d x d t =2(2 t-3)(2) At origin, x=0 array lc & 2 t-3=0 t= 3 2 & Velocity = d x d t =4 (2 3 2 -3 )=0 array