A man is standing on the horizontal plane. The angle of elevation of top of the pole is . If he walks a distance double the height of the pole, then the elevation of the pole is 2 . The value of is

Step-by-step solution

Let the height of the pole be B C=h ~m . In A B C , 2 = h x ....(i) and in D B C , = h 2 h+x = h x 2 ( h x )+1 = 2 2 2 +1 (2 2 +1)= 2 [2 2 1- ^2 +1 ]= 2 1- ^2 [4 +1- ^2 ]=2 ^2 -4 +1=0= 4 12 2 = 4 2 3 2 Taking '-' sign, we get =2- 3 = 15^ =15^ or 12