Manipal MET2011MathematicsHyperbola
The distance between the foci of a hyperbola is double the distance between its vertices and the length of its conjugate axis is 6 .The equation of the hyperbola referred to its axes as axes of coordinates are
Options
- A3 x^2-y^2=3
- Bx^2-3 y^2=3
- C3 x^2-y^2=9
- Dx^2-3 y^2=9
Correct answer
C. 3 x^2-y^2=9
Step-by-step solution
According to given condition, 2 a e=2 2 a e=2 and 2 b=6 b=3 Hence, a= 3 3 = 3 Required equation is aligned & x^2 3 - y^2 9 =1 & 3 x^2-y^2=9 aligned