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Manipal MET2015MathematicsLimits

If f(x)= (e^ x-2 -1 ) (x-1) , then _ x 2 f(x) is given by

Options

  1. A-2
  2. B-1
  3. C0
  4. D1

Correct answer

D. 1

Step-by-step solution

We have, _ x 2 f(x)= _ x 2 (e^ x-2 -1 ) (x-1) aligned &= _ x 2 (e^ x-2 -1 ) e^ x-2 -1 e^ x-2 -1 x-2 x-2 [1+(x-2)] aligned =1 1 1=1

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