According to Newton-Raphson method, the value of 12 upto three places of decimal will be

Step-by-step solution

Let x= 12 x^2=12 x^2-12=0 Let f(x)=x^2-12 The first approximation in the Newton-Raphson method is given by x₁=x₀- f (x₀ ) f^ (x₀ ) =x₀- x₀^2-12 2 x₀ = x₀^2+12 2 x₀ 3 12 3.5 We can take x₀=3.5 x₁= (3.5)^2+12 2 3.5 = 12.25+12 7 = 24.25 7 =3.464