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Manipal MET2016MathematicsPair of Lines

The foci of the conic section 25 x^2+16 y^2-150 x=175 are

Options

  1. A(0, 3)
  2. B(0, 2)
  3. C(3, 3)
  4. D(0, 1)

Correct answer

C. (3, 3)

Step-by-step solution

Given equation can be written as (x-3)^2 16 + y^2 25 =1 aligned & Here, a^2=16 and b^2=25 & e= 1- 16 25 = 3 5 aligned Hence, the foci of conic section are (0, b e) i.e. (3, 3) .

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