Manipal MET2011MathematicsPair of Lines
If the equation 12 x^2+7 x y-p y^2-18 x+q y+6=0 represents a pair of perpendicular straight lines, then
Options
- Ap=12, q=-1
- Bp=-12, q=1
- Cp=12, q=1
- Dp=1, q=1
Correct answer
C. p=12, q=1
Step-by-step solution
The second degree equation will represent a pair of perpendicular straight lines, if | array lll a & h & g h & b & f g & f & c array |=0 and a+b=0 Given pair of line is 12 x^2+7 x y-p y^2-18 x+q y+6=0 | array ccc 12 & 7 / 2 & -9 7 / 2 & -p & q / 2 -9 & q / 2 & 6 array |=0 array ll and & 12-p=0 & p=12 array | array ccc 12 & 7 / 2 & -9 7 / 2 & -12 & q / 2 -9 & q / 2 & 6 array |=0 aligned & 12 (-72+ q^2 4 )- 7 2 (-21+ 9 q 2 ) & -9 ( 7 q 4 -108 )=0 & -864-3 q^2- 147 2 - 63 q 4 & - 63 q 4 +972=0 q=1 aligned