Manipal MET2015MathematicsParabola
If the line x-1=0 is the directrix of the parabola y^2-k x+8=0 , then one of the value of k is
Options
- A1 8
- B8
- C4
- D1 4
Correct answer
C. 4
Step-by-step solution
Given equation of parabola is y^2-k x+8=0 array lr & y^2=k (x- 8 k ) & (y-0)^2=k (x- 8 k ) array The equation of the directrix of this parabola is x- 8 k =- k 4 [ x=-a] x= 8 k - k 4 But the equation of the directrix is given as x-1=0 . 8 k - k 4 =1 aligned & & k^2+4 k-32 & =0 & & (k-4)(k+8) & =0 & & k & =-8,4 aligned