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Manipal MET2011MathematicsParabola

The equation of parabola whose vertex and focus are (0,4) and (0,2) respectively, is

Options

  1. Ay^2-8 x=32
  2. By^2+8 x=32
  3. Cx^2+8 y=32
  4. Dx^2-8 y=32

Correct answer

C. x^2+8 y=32

Step-by-step solution

Since, vertex is (0,4) and focus is (0,2) . a=2 Equation of parabola is aligned & (x-0)^2=-4 2(y-4) & x^2+8 y=32 aligned

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