Probability of getting a total of 7 or 9 in a single throw of two dice is

Step-by-step solution

The total number of sample points in a sample space of single throw of two dice, n(S)=36 Let E₁= Event of getting a sum 7 E₂= Event of getting a sum 9 E₁= (1,6),(6,1),(2,5),(5,2),(3,4),(4,3) n (E₁ )=6 and E₂= (3,6),(6,3),(4,5),(5,4) n (E₂ )=4 P (E₁ )= n (E₁ ) n(S) = 6 36 = 1 6 and P (E₂ )= n (E₂ ) n(S) = 4 36 = 1 9 Nơw, P (E₁ E₂ )=P (E₁ )+P (E₂ )= 1 6 + 1 9 = 6+4 36 = 10 36 = 5 18