A die is rolled three times. The probability of getting a larger number than the previous number is

Step-by-step solution

When a die is rolled three times. Then, cardinality of sample space =6^3 Now, according to question, the favourable outcomes aligned = & (1,2,3),(1,2,4),(1,2,5),(1,2,6), & (1,3,4),(1,3,5),(1,3,6),(1,4,5), & (1,4,6),(1,5,6),(2,3,4),(2,3,5), & (2,3,6),(2,4,5),(2,4,6),(3,4,5), & (3,4,6),(4,5,6),(2,5,6),(3,5,6) aligned Required probability = 20 6^3 = 5 54