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Manipal MET2017MathematicsProperties of Triangles

The equation of the circle circumscribing the triangle formed by the lines x+y=6 , 2 x+y=4 and x+2 y=5 is

Options

  1. Ax^2+y^2+17 x+19 y-50=0
  2. Bx^2+y^2-17 x-19 y-50=0
  3. Cx^2+y^2+17 x-19 y-50=0
  4. Dx^2+y^2-17 x-19 y+50=0

Correct answer

D. x^2+y^2-17 x-19 y+50=0

Step-by-step solution

Lines, x+y=6,2 x+y=4 and x+2 y=5 intersect at points (-2,8),(7,-1) and (1,2) . Now, all these points lie on x^2+y^2-17 x-19 y+50=0

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