Manipal MET2013MathematicsQuadratic Equation
If b 0 , then the roots x₁ and x₂ of the equation 2 x^2+6 x+b=0 , satisfy the condition ( x₁ x₂ )+ ( x₂ x₁ ) K , where K is equal to
Options
- A2
- B-2
- C0
- D4
Correct answer
B. -2
Step-by-step solution
The discriminant of the quadratic equation 2 x^2+6 x+b=0 is given by D=36-8 b 0 . Therefore, the given equation has real roots. we have, x₁ x₂ + x₂ x₁ = x₁^2+x₂^2 x₁ x₂ = (x₁+x₂ )^2-2 x₁ x₂ x₁ x₂ = (-3)^2-2(b / 2) (b / 2) = 18 b -2 -2 [ b 0]